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American Mineralogist; February 2004; v. 89; no. 2-3; p. 405-420
© 2004 Mineralogical Society of America
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Structural variations in the brownmillerite series Ca2(Fe2–xAlx)O5: Single-crystal X-ray diffraction at 25 °C and high-temperature X-ray powder diffraction (25 °C ≤ T ≤ 1000 °C)

Günther J. Redhammer1,*, Gerold Tippelt2, Georg Roth1 and Georg Amthauer2

1 Institute of Crystallography, Rheinisch-Westfalische Technische Hochschule Aachen, Jagerstrasse 17/19, D-52056 Aachen, Germany
2 Institute of Mineralogy, University of Salzburg, Hellbrunnerstrasse 34, A-5020 Salzburg, Austria

Correspondence: * E-mail: guenther.redhammer{at}aon.at

A total of 30 synthetic samples of the Ca2Fe2–xAlxO5, 0.00 ≤ x ≤ 1.34 solid solution series have been investigated by single crystal X-ray diffraction at 25 °C. Pure Ca2Fe2O5 and samples up to x = 0.56 have space group Pnma, Z = 4, whereas samples with x >0.56 show I2mb symmetry, Z = 4. The substitution of Fe3+ by the smaller Al3+ cation decreases unit-cell parameters and average octahedral and tetrahedral bond lengths and induces distinct changes in the O-atom coordination of the interstitial Ca atom. Discontinuities in the structural parameters vs. the Al3+tot content and changes in slope of these quantities are associated with the phase transition. The essential difference between the two modifications is the cation-O atom-cation angle within the planes of corner sharing octahedra, which is close to 180° in I2mb, but {approx}184° in the Pnma phase, and the existence of two different orientations of the tetrahedral chains in Pnma as opposed to one in I2mb. At low overall Al3+ concentrations Al3+ preferentially enters the tetrahedral site until {approx}2/3 of it is filled. Additional Al3+ cations, substituted for Fe3+, are equally distributed over octahedral and tetrahedral sites. At high temperature pure Ca2Fe2O5 transforms to a body-centered structure at 724(4)°C. Substituting Al3+ for Fe3+ linearly decreases the transition temperature by 15 °C per 0.1 Al3+ down to 623(5)°C for x = 0.65.







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